UGC NET CS 2009 Dec-Paper-2 | Parsers

1. A → a A b, A → b A b, A → a , A →b
2. A → a A a, A → a A b, A → c
3. A → A + A, A → a
4. Both (A) and (B)

Answer : D

Explanation:
Both (A) and (B)
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