Question 1 |
For the operational amplifier circuit shown, the output saturation voltages are ±15V. The upper and lower threshold voltages for the circuit are, respectively.
+5V and -5V | |
+7V and -3V | |
+3V and -7V | |
+3V and -3V |
Question 1 Explanation:
Question 2 |
An ideal op-amp has voltage sources V1, V3, V5, ..., VN-1 connected to the non-inverting input and V2,V4, V6, ..., VN connected to the inverting input as shown in the figure below (+Vcc= 15 volt,—Vcc= —15 volt). The voltages V1, V2, V3, V4, V5, V6,... are 1, — 1/2, 1/3, —1/4, 1/5, —1/6,... volt, respectively. As N approaches infinity, the output voltage (in volt) is
Fill in the Blank Type Question |
Question 2 Explanation:
Question 3 |
For the NMOSFET in the circuit shown, the threshold voltage is Vth, where Vth > 0. The source voltage VSS is varied from 0 to VDD. Neglecting the channel length modulation, the drain current ID as a function of VSS is represented by
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Question 3 Explanation:
Hence MOS transistor is in saturation.
In saturation,
As Vss increases ID decreases (Not linearly because square factor)
Hence option A. is correct.
Question 4 |
In the op-amp circuit shown, the Zener diodes Z1 and Z2 clamp the output voltage Vo to +5 V or -5V. The switch S is initially closed and is opened at time t=0
The time t = t1 (in seconds) at which Vo changes state is ____
The time t = t1 (in seconds) at which Vo changes state is ____
Fill in the Blank Type Question |
Question 4 Explanation:
Question 5 |
An op-amp has a finite open loop voltage gain of 100. Its input offset voltage
Vios(= +5 mV)
is modeled as shown in the circuit below. The amplifier is ideal in all other respects.
Vinput Is 25 mV
The output voltage (in millivolts) is _____
Vinput Is 25 mV
The output voltage (in millivolts) is _____
Fill in the Blank Type Question |
Question 5 Explanation:
The gain of the practical op-amp
Question 6 |
In the circuit shown, assume that the opamp is ideal. If the gain (v0 / vin) is –12, the value of R (in kΩ) is _____.
Fill in the Blank Type Question |
Question 6 Explanation:
Given
Question 7 |
In the ac equivalent circuit shown in the figure, if iin is the input current and RF is very large, the type of feedback is
voltage-voltage feedback | |
voltage-current feedback | |
current-voltage feedback | |
current-current feedback |
Question 7 Explanation:
Output sample is voltage and is added to the input current.
Since, feedback is diectly connected to output so the sampling is voltage and mixing is current type.
∴ It is voltage – shunt negative feedback i.e., voltage-current negative feedback
Since, feedback is diectly connected to output so the sampling is voltage and mixing is current type.
∴ It is voltage – shunt negative feedback i.e., voltage-current negative feedback
Question 8 |
The feedback topology in the amplifier circuit (the base bias circuit is not shown for simplicity) in the figure is
Voltage shunt feedback | |
Current series feedback | |
Current shunt feedback | |
Voltage series feedback |
Question 8 Explanation:
By opening the output feedback signed becomes zero. Hence it is current sampling. As the feedback signal vf is subtracted from the signal same vs it is series mixing.
Question 9 |
An analog voltage in the range 0 to 8 V is divided in 16 equal intervals for conversion to 4-bit digital output. The maximum quantization error (in V) is _________________
0.20 | |
0.25 | |
0.30 | |
0.40 |
Question 9 Explanation:
Dynamic range or voltage range = 0 to 8 V
Number of levels = 16
Maximum quantization error Qe =stepsize(Δ)/2
Where Δ = Dynamic Range/L = 8/24 =8/16=0.5
Therefore Maximum quantization error = 0.5/2 =0.25 V
Number of levels = 16
Maximum quantization error Qe =stepsize(Δ)/2
Where Δ = Dynamic Range/L = 8/24 =8/16=0.5
Therefore Maximum quantization error = 0.5/2 =0.25 V
Question 10 |
The circuit shown is a
Low pass filter with  | |
High pass filters with  | |
Low pass filter with  | |
High pass filter with  |
Question 10 Explanation:
T(s) = 
T(s) =
It is the transfer function of high pass filter with cutoff frequency → ω =
rad/sec
T(s) =
It is the transfer function of high pass filter with cutoff frequency → ω =
rad/secQuestion 11 |
The voltage gain Av of the circuit shown below is
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 |
Question 11 Explanation:
Apply Miller's theorem to 100 k resistor
Question 12 |
For the same network, with 6 V dc connected at port A, 1 Ω connected at port B draws 7/3A. If 8 V dc is connected to port A. the open circuit voltage at port B is
6 V | |
7 V | |
8 V | |
9 V |
Question 12 Explanation:
There are 12 questions to complete.