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Question 1 |

For the operational amplifier circuit shown, the output saturation voltages are ±15V. The upper and lower threshold voltages for the circuit are, respectively.

+5V and -5V | |

+7V and -3V | |

+3V and -7V | |

+3V and -3V |

Question 2 |

An ideal op-amp has voltage sources V

_{1}, V_{3}, V_{5}, ..., V_{N-1}connected to the non-inverting input and V_{2},V_{4}, V_{6}, ..., V_{N}connected to the inverting input as shown in the figure below (+V_{cc}= 15 volt,—V_{cc}= —15 volt). The voltages V_{1}, V_{2}, V_{3}, V_{4}, V_{5,}V_{6},... are 1, — 1/2, 1/3, —1/4, 1/5, —1/6,... volt, respectively. As N approaches infinity, the output voltage (in volt) isFill in the Blank Type Question |

Question 3 |

For the NMOSFET in the circuit shown, the threshold voltage is V

_{th}, where V_{th}> 0. The source voltage V_{SS}is varied from 0 to V_{DD}. Neglecting the channel length modulation, the drain current I_{D}as a function of V_{SS}is represented byQuestion 3 Explanation:

Hence MOS transistor is in saturation.

In saturation,

As V

_{ss}increases I

_{D}decreases (Not linearly because square factor)

Hence option A. is correct.

Question 4 |

In the op-amp circuit shown, the Zener diodes Z

_{1}and Z_{2}clamp the output voltage V_{o}to +5 V or -5V. The switch S is initially closed and is opened at time t=0 The time t = t_{1}(in seconds) at which V_{o}changes state is ____Fill in the Blank Type Question |

Question 4 Explanation:

Question 5 |

An op-amp has a finite open loop voltage gain of 100. Its input offset voltage

The output voltage (in millivolts) is _____

**V**is modeled as shown in the circuit below. The amplifier is ideal in all other respects._{ios}(= +5 mV)**V**Is_{input}**25 mV**The output voltage (in millivolts) is _____

Fill in the Blank Type Question |

Question 5 Explanation:

The gain of the practical op-amp

Question 6 |

In the circuit shown, assume that the opamp is ideal. If the gain (v

_{0}/ v_{in}) is –12, the value of R (in kΩ) is _____.Fill in the Blank Type Question |

Question 6 Explanation:

Given

Question 7 |

In the ac equivalent circuit shown in the figure, if i

_{in}is the input current and R_{F}is very large, the type of feedback isvoltage-voltage feedback | |

voltage-current feedback | |

current-voltage feedback | |

current-current feedback |

Question 7 Explanation:

Output sample is voltage and is added to the input current.

Since, feedback is diectly connected to output so the sampling is voltage and mixing is current type.

∴ It is voltage – shunt negative feedback i.e., voltage-current negative feedback

Since, feedback is diectly connected to output so the sampling is voltage and mixing is current type.

∴ It is voltage – shunt negative feedback i.e., voltage-current negative feedback

Question 8 |

The feedback topology in the amplifier circuit (the base bias circuit is not shown for simplicity) in the figure is

Voltage shunt feedback | |

Current series feedback | |

Current shunt feedback | |

Voltage series feedback |

Question 8 Explanation:

By opening the output feedback signed becomes zero. Hence it is current sampling. As the feedback signal v

_{f}is subtracted from the signal same v_{s}it is series mixing.Question 9 |

An analog voltage in the range 0 to 8 V is divided in 16 equal intervals for conversion to 4-bit digital output. The maximum quantization error (in V) is _________________

0.20 | |

0.25 | |

0.30 | |

0.40 |

Question 9 Explanation:

Dynamic range or voltage range = 0 to 8 V

Number of levels = 16

Maximum quantization error Q

Where Δ = Dynamic Range/L = 8/2

Therefore Maximum quantization error = 0.5/2 =0.25 V

Number of levels = 16

Maximum quantization error Q

_{e}=stepsize(Δ)/2Where Δ = Dynamic Range/L = 8/2

^{4}=8/16=0.5Therefore Maximum quantization error = 0.5/2 =0.25 V

Question 10 |

Low pass filter with | |

High pass filters with | |

Low pass filter with | |

High pass filter with |

Question 10 Explanation:

T(s) =

T(s) =

It is the transfer function of high pass filter with cutoff frequency → ω = rad/sec

T(s) =

It is the transfer function of high pass filter with cutoff frequency → ω = rad/sec

Question 11 |

Question 11 Explanation:

Apply Miller's theorem to 100 k resistor

Question 12 |

For the same network, with 6 V dc connected at port A, 1 Ω connected at port B draws 7/3A. If 8 V dc is connected to port A. the open circuit voltage at port B is

6 V | |

7 V | |

8 V | |

9 V |

There are 12 questions to complete.