A voltage 1000 sin ωt Volts is applied across YZ. Assuming ideal diodes, the voltage measured across WX in Volts, is
- sin ωt
- (sin ωt + |sin ω t|)/2
- (sin ωt – |sin ω t|)/2
- 0 for all t
Answer : D
Explanation:
**The Correct Answer Among All the Options is D
Given, the input voltage
For + ve half cycle
i.e., VY is a higher voltage than VZ
So, the diode will be in cutoff region. Therefore, there will no voltage difference between X and W node.
i.e., 
Now, for –ve half cycle all the four diodes will active and so, X and W terminal is short circuited
i.e, 
Hence, 
for all t
Hence correct option is D. Practice Topic Wise Solved ECE PSU & Gate Question for Simple Diode and Wave Shaping Circuitsa , Analog Circuits
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